Pure Water

Chemistry Level 3

For pure water at 25 degree celcius , the correct options are

A. \(\ce{[H2O]}\) = 55.56 \(\text{ mol } {dm}^{-3}\) if density of water is 1 \( \text{ g} {cm}^{-3}\)

B. \({K}_{w}\) = \( {10}^{-14} {(\text{ mol } {dm}^{-3})}^{2}\)

C. Degree of dissociation = 1.8 \(\times\) \({10}^{-9}\)

D. Ionisation constant , \({K}_{ionisation}\) = 1.8 \(\times\) \({10}^{-16}\).


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This is a part of my set Aniket's Chemistry Challenges. (BEST OF JEE - ADVANCED)
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