Forgot password? New user? Sign up
Existing user? Log in
Use the Pythagorean identity sin2(x)+cos2(x)=1\sin^2(x) + \cos^2(x) = 1sin2(x)+cos2(x)=1 to find the value of cos(x)\cos(x)cos(x) if sin2(x)+2cos(x)−2=0\sin^2(x) + 2\cos(x) - 2 = 0sin2(x)+2cos(x)−2=0. Enter your answer as the value of cos(x)\cos(x)cos(x).
Problem Loading...
Note Loading...
Set Loading...