An AC power supply with a voltage ($$V_s$$) of $$15\text{ V}$$ and a frequency ($$f$$) of $$30\text{ Hz}$$ was connected to a circuit of four capacitors ($$C$$).

In this circuit, $$C_\text{I} = \dfrac{10}{\pi}\text{ F}$$, $$C_\text{II} = \dfrac{4}{\pi}\text{ F}$$, $$C_\text{III} = \dfrac{6}{\pi}F$$, and $$C_\text{IV} = \dfrac{20}{\pi}\text{ F}$$.

Determine the current ($$I$$) of this circuit in $$\text{amps}$$.

Note: $$X_c = \dfrac{1}{2 \pi \text{ f }C_\text{circuit}}$$ and $$I = \dfrac{V_s}{X_c}$$.

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