Quadratic and Trigonometry for JEE #2

Algebra Level 4

Let xx and yy be the roots of the equation asin2θ+bsinθ+c=0 a \sin^{2}\theta + b \sin\theta +c =0 such that sinx+2siny=1\sin x + 2 \sin y = 1 then find the value of (2015)(a2+2b2+3ab+ac)(2015)*( a^{2}+2b^{2}+3ab+ac)

Given that a,b,c are real numbers such that a0a\neq 0.

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