Forgot password? New user? Sign up
Existing user? Log in
In △ABC\triangle ABC△ABC, ∠A=90∘\angle A = 90^\circ∠A=90∘, AC=3AC = 3AC=3 and AB=4AB=4AB=4. CDCDCD is the angle bisector of ∠ACB\angle ACB∠ACB. Point EEE on ACACAC is such that CE=AECE=AECE=AE. CDCDCD and BEBEBE intersect at MMM. If the area of quadrilateral ADME=abADME= \dfrac abADME=ba, where aaa and bbb are positive coprime integers, find a+ba+ba+b.
Problem Loading...
Note Loading...
Set Loading...