Question 4

Geometry Level 3

If aa , bb , cc are the sides of a triangle and 2a+3b+4c=42a2+63b3+84c4202a +3b+4c = 4\sqrt{2a-2}+ 6\sqrt{3b-3}+8\sqrt{4c-4}-20 then the area of triangle is:


This question is part of the set For the JEE-nius;P
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