# Question -7

If $$\displaystyle \sum_{i=1}^{18} (x_i-8)=9$$ and $$\displaystyle \sum_{j=1}^{18} (x_j-8)^2=45$$, then the standard deviation of $$x_1,x_2,x_3,...,x_{18}$$ is:

###### Looking for Top Rank in JEE? Alright, then go for this set : Expected JEE-Mains-2015-B.
×

Problem Loading...

Note Loading...

Set Loading...