if 1/(a+w)+1/(b+w)+1/(c+w)+1/(d+w)=2/w where a,b,c are real and w is a non real cube root of unity find the value of X and Y. express your answer as the sum of X and Y .i.e. (X+Y) when -
(a+b+c+d)=X
AND
1/(a+1)+1/(b+1)+1/(c+1)+1/(d+1)=Y

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