We have an acute angled triangle $$ABC$$ and it's orthocenter is $$H$$.$$AH$$ extended meets $$BC$$ at $$D$$ and $$CH$$ extended meets $$AB$$ at $$E$$.$$DE$$ meets $$BH$$meet at $$K$$ and midpoint of $$BH$$ is $$M$$.What is the angle between $$AK$$ and $$CM$$ in degrees??????????.Answer may be too easy to guess but please do provide a good proof. The problem may be easy and also well.known but I found it out while performing some radical-axis theorems.