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If x^\sqrt{x}=729, y^\sqrt{y}=65536, z^\sqrt{z}=16, $x+y+z+\sqrt{a+b}=32$ and $x+y+z+\sqrt{a-b}=30$, then find

$\large (x+y+z+a+b-2)^{\frac {\sqrt{x+y+z+a+b-2}} 3}$

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