\[\tan \theta = \dfrac{1}{3}\] \[\implies \sin \theta = \dfrac{ \sqrt{a}}{b}\] or \[\implies \sin \theta = - \frac{ \sqrt{a}}{b}\] where \( \dfrac{ \sqrt{a}}{b}\) is in simplest form. Find \(a+b\)

Both \(a\) and \(b\) is a positive integers.

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