# Ratio :)

Geometry Level 3

$\tan \theta = \dfrac{1}{3}$ $\implies \sin \theta = \dfrac{ \sqrt{a}}{b}$ or $\implies \sin \theta = - \frac{ \sqrt{a}}{b}$ where $$\dfrac{ \sqrt{a}}{b}$$ is in simplest form. Find $$a+b$$

# Details

Both $$a$$ and $$b$$ is a positive integers.

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