# Rationalizing.. It's easy, isn't it?

Algebra Level pending

$\dfrac{\sqrt[3]{3}}{2+3\sqrt[3]{3}+2\sqrt[3]{9}}$

The above expression can be rationalized into the form $$\dfrac{a-b\sqrt[3]{3}+c\sqrt[3]{9}}{d}$$. Where $$gcd(a, b, c, d)=1$$. Evaluate $$a+b+c+d$$.

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