Real values!

Algebra Level 4

Find the value of a-a for which the roots x1,x2,x3x_{1}, x_{2}, x_{3} of x36x2+axa=0x^{ 3 }-6x^{2}+ax-a = 0 satisfy (x13)3+(x23)3+(x33)3=0\left( x_{1}-3 \right)^{3}+\left(x_{2}-3 \right)^{3}+\left(x_{3}-3 \right)^{ 3 } = 0.

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