# Real values!

Algebra Level 4

Find the value of $-a$ for which the roots $x_{1}, x_{2}, x_{3}$ of $x^{ 3 }-6x^{2}+ax-a = 0$ satisfy $\left( x_{1}-3 \right)^{3}+\left(x_{2}-3 \right)^{3}+\left(x_{3}-3 \right)^{ 3 } = 0$.

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