# Real values!

Algebra Level 5

Find the value of $$-a$$ for which the roots $$x_{1}, x_{2}, x_{3}$$ of $$x^{ 3 }-6x^{2}+ax-a = 0$$ satisfy $$\left( x_{1}-3 \right)^{3}+\left(x_{2}-3 \right)^{3}+\left(x_{3}-3 \right)^{ 3 } = 0$$.

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