Reciprocal sum is exactly 1 now

Find the number of solutions to the equation 1a+1b+1c+1d=1\frac{1}{a}+ \frac{1}{b}+ \frac{1}{c} +\frac{1}{d}=1 where a, b, c, da,\ b,\ c,\ d are positive integers and abcd.a\leq b \leq c \leq d.

×

Problem Loading...

Note Loading...

Set Loading...