Determine the horizontal velocity \(v\) with which a stone must be projected horizontally from a point \(P\), so that it may hit the inclined plane perpendicularly. The inclination of the plane with the horizontal is \(x\) and point \(P\) is at a height \(h\) above the foot of the incline.

Details And assumptions

Take \(g=10\frac{\text{m}}{\text{s}^2}\)

\(h = 10\text{ m}\)

\(x = {45}^{\circ}\)

Round off the answer to the nearest integer.

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