Recurring Styles #2 - Recurrence on Higher Degrees!
Calculus
Level
5
\[\Large{\frac{a_n}{a_{n-1}} = \sqrt[6]{\frac{a_{n-1}}{a^2_{n-2}}}}\]
Define a sequence \(a_n\) that satisfies the recurrence relation as described above where \(n \geq 2 , a_0 = e , a_1 = e^2\).
Find the value of \(\displaystyle\large{ \lim_{n \to \infty} a_n}\).
Bonus: Generalize for \(a_n\).
by
Satyajit Mohanty