In **case 2** ignore the first term **1**, but take the first term (1) of **case 1** in account, and consider **2** as first term **4** as second term etc..,.

If \(a_n\) and \(b_n\) are \(n^{th}\) terms of case 1 and case 2 respectively, and \(A_n\) and \(B_n\) represents sum to \(n^{th}\) term of case 1 and case 2 respectively, **find the value of** \(B_{n-1} - A_n\)

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