Relativistic Rotating Disk

A disk with radius R=1 mR=1 \space m is rotating with a large angular velocity of ω=2.5108 s1\omega =2.5\cdot { 10 }^{ 8 }\space s^{ -1 }. According to relativistic kinematics, what is the ratio of the disk's circumference to its radius, as observed in an inertial frame where the disk does not translate?

Bonus Thought: According to elementary geometry, the answer is 2π2 \pi. Is it? If not, what's going on here?

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