Resistors in infinite series

\[ \text{For} \space a > 1: \\ R = \tau (a) = \sum_{n=0}^{\infty} \frac{1}{a^n} = \frac{a}{a-1} \\ and \\ V = IR\]

A circuit consisting of an infinite series of resistors is prepared such that the simplified equivalent resistor has a resistance (\(R\)) equal to \(\tau (a) \). Determine the voltage (\(\text{V}\)) a circuit that has a resistance of \(\tau (5) \space Ω \) and a current (\(\text{I}\)) of \(16 \space A\).

Give your answer in volts.

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