# Reversed Multiples

Let the reverse of a positive integer $$n$$, denoted $$R(n),$$ be the result when the digits of the number are written backwards; for example, $$R(190) = 091,$$ or just $$91.$$

Call a positive integer $$n$$ brilliant if $n + R(n)$

is a multiple of 13. Let $$B$$ be the $$10000$$th brilliant number. Compute the last three digits of $$B.$$

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