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Given an isosceles right triangle ABCABCABC, such that:
AB=AC=1,∠BAC=π2{AB=AC=1, \quad \angle BAC = \dfrac{\pi}2}AB=AC=1,∠BAC=2π
Let DDD be a point inside the triangle such that:
∠ADB=π2,∠ABD=∠BCD{\angle ADB = \dfrac{\pi}2, \quad \angle ABD = \angle BCD}∠ADB=2π,∠ABD=∠BCD
Find the area of △ABD\triangle ABD△ABD.
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