Roam around in the Space

Geometry Level 3

The surface area of a surface in three dimensional space represented by the equation \[x^2+y^2+z^2-2 \alpha x-4\alpha y-6 \alpha z-8\alpha^2=0\] for some positive real \(\alpha,\) is 88. If \(\alpha = \pi^a\) then find \(16a\).

×

Problem Loading...

Note Loading...

Set Loading...