Rotating a Triangle

Acute triangle $ABC$ has its vertices labeled in a clockwise manner. It is rotated $90^\circ$ counter-clockwise about $C$ to get $A’B’C$. Let $D$ be the midpoint of $AB’$. If $\lvert BA’ \rvert = 1202$, what is $\lvert CD \rvert$?

Details and assumptions

$|XY|$ denotes the straight line distance from $X$ to $Y$.
Due to the rotation in the question, I am explicitly denoting that we are measuring the straight line distances, as opposed to the arc length of the sector.