Rotating charged half ring

A charged half ring of radius RR is held fixed on a plane. Let the center of the half ring be OO.

Let us complete the circle C C which contains the half ring. A point PP is taken on the circumference of CC, such that PO\overrightarrow {PO} passes through the center of mass of the half ring.

The plane is then rotated with an angular velocity ω\omega about an axis passing through PP and perpendicular to the plane.

Find the value of BPEP1016\dfrac {|\vec{B_P}|}{|\vec{E_P}|} \cdot 10^{16} where BP|\vec{B_P}| and EP|\vec{E_P}| are the magnitudes of magnetic and electric fields at point P P respectively.

Assumptions\textbf{Assumptions}

   \bullet \ \ \ The mass distribution of the half ring is uniform.

    \bullet \ \ \ \ The charge distribution of the half ring is uniform.

    \bullet \ \ \ \ The above procedure is carried out in vacuum, so the permeability μo=4π×107 H/m\mu_{o}=4\pi \times 10^{-7} \ \text {H/m}

    \bullet \ \ \ \ When the plane rotates, the angular velocity of the half ring with respect to the plane is 00

    \bullet \ \ \ \ Coulomb's constant k=9×109 Nm2/C2k=9 \times 10^9 \ \text {N} \text{m}^2/\text {C}^2

    ω=9 rad/s\bullet \ \ \ \ \omega=9 \ \text{rad/s}

    R=1 m\bullet \ \ \ \ R=1 \ \text{m}

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