# Rotational Motion At Its Best !

A uniform thin rod of mass m and length $$l$$ is standing on a smooth horizontal surface. A slight disturbance causes the lower end to slip on the smooth surface and the rod starts falling. Find the velocity of centre of mass of the rod at the instant when it makes angle θ with the horizontal.

The answer can be expressed in the form of $$\sqrt{\frac{agl(1 - sinθ)cos^{2}θ}{(b + dcos^{2}θ)}}$$ where a,b,d are positive integers. and b,d are co-prime

Find value of a+b+d ?

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