# Same digits, again?

I have an integer $$n$$ in my mind which satisfies following properties:

• The reciprocal $$m$$ of $$n$$ is a non-terminating recurring decimal
• The recurring digits of $$m$$ forms a number $$p$$. For example, recurring digits of reciprocal of 13 forms a number 769230 and digits of reciprocal of 9 forms 1. (Move 0 to the end if it appears at first place as I did in case of 13)
• $$p$$ is the smallest number such that the digits of $$p$$ are same as that of $$2p,\ 3p,\ 4p,\ 5p$$ and $$6p$$

Enter your answer as $$p+n$$

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