Saponification

Chemistry Level 2

An ester in aqueous solution is split by the addition of sodium hydroxide in a carboxylate and an alcohol (saponification). After a period of two minutes, the ester concentration has decreased by 20%.

How long does it take to convert 80% of the ester?

Details: The saponification is a second-order reaction with the reaction rate r=k2[Ester][OH],r = k_2 \cdot [\text{Ester}] \cdot [\text{OH}^-], where k2k_2 is the reaction constant. The initial concentrations of ester and hydroxide are both equal: [Ester]0=[OH]0.[\text{Ester}] _0 = [\text{OH}^-]_0.

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