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Given that {an}\{a_n\}{an} is a geometric progression with common ratio q=2q=\sqrt{2}q=2. Let Sn=∑k=1nakS_n=\displaystyle \sum_{k=1}^n a_kSn=k=1∑nak and Tn=17Sn−S2nan+1T_n=\dfrac{17 S_n - S_{2n}}{a_{n+1}}Tn=an+117Sn−S2n, where nnn is a positive integer. If TmT_{m}Tm is the maximum term of sequence {Tn}\{T_n\}{Tn}, find mmm.
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