# Saurav's Square #4

**Number Theory**Level pending

Let X be a smallest 9 digit number such that last 9 digits of the square of number X is the number (X) itself. Find the digit sum of the digit sum of number X.

For eg. Let the number be 789. so, the digit sum of the digit sum of 789 : 7+8+9 = 24 2+4 = 6. So, the answer will be 6.