\[\large \lim_{x\rightarrow 0} \left\{\sin^{2}\left(\dfrac{\pi}{2-ax}\right)\right\}^{\sec^{2}\left(\frac{\pi}{2-bx}\right)}\]

If the value of the above limit is in the form \(e^{k\left(\frac{a^2}{b^2}\right)}\), where \(k\) is a integer, then find \(-2017k\).

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