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$\beta$ =$\displaystyle \lim_{ x \rightarrow \infty} \dfrac{(2^{x^n})^{{1}/{e^x}} -(3^{x^n})^{{1}/{e^x}} }{x^n}$

Given That n $\epsilon$ N.

Find $2^{\beta} + 2^{\beta +1}$.

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