\(\beta \) =\( \displaystyle \lim_{ x \rightarrow \infty} \dfrac{(2^{x^n})^{{1}/{e^x}} -(3^{x^n})^{{1}/{e^x}} }{x^n} \)

Given That n \(\epsilon\) N.

Find \(2^{\beta} + 2^{\beta +1}\).

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