Two protons and two positrons form a square as shown in the figure. All the particles are initially at rest. Due to Coulomb's repulsion, the particles fly off to infinity. Determine the ratio \( \frac{v_{p}}{v_{e}}\) where \( v_{p}\) and \( v_{e}\) are the final velocities of the protons and positrons, respectively. Note that the positron, being electron's antiparticle, has the same mass as the electron and opposite charge \((q=+1.6\times 10^{-19}~\textrm{C})\).

**Details and assumptions**

- \( \frac{m_{p}}{m_{e}}=1836\)
- Hint: since the protons are so much heavier, you can do this without having to solve momentum conservation. Think about which particles fly away first...

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