Series
Calculus
Level
3
If \(\displaystyle \sum_{n=1}^\infty \dfrac1{n^2} = \dfrac{\pi^2}6 \), then what is the value of \( \displaystyle \sum_{n=1}^\infty \dfrac1{(2n-1)^2} \)?
Give your answer to 3 decimal places.
by
Trishit Chandra