Series

Calculus Level 3

If n=11n2=π26\displaystyle \sum_{n=1}^\infty \dfrac1{n^2} = \dfrac{\pi^2}6 , then what is the value of n=11(2n1)2 \displaystyle \sum_{n=1}^\infty \dfrac1{(2n-1)^2} ?

Give your answer to 3 decimal places.

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