Brilliant

Today Courses

Algebra
Geometry
Number Theory
Calculus
Probability
Basic Mathematics
Logic
Classical Mechanics
Electricity and Magnetism
Computer Science
Quantitative Finance
Chemistry

Excel in math and science.

Log in with Facebook Log in with Google Log in with email

Join using Facebook Join using Google Join using email

Forgot password? New user? Sign up

Existing user? Log in

See Reese

Algebra Level 2

The $n^{th}$ term of the series $1^2 , ( 1^2 + 2^2 ) , ( 1^2 + 2^2 + 3^2 )$ , $\ldots$ is?

\frac{ n(n + 1)(2n + 1) }{6}

\frac{ n(n + 1) }{2}

\frac{n^2 (n + 1)^2 }{2}

n^2 + (n - 1)^2 + (n - 2)^2

View solutions

Your answer seems reasonable. Find out if you're right!

Sign up to access problem solutions.

That seems reasonable. Find out if you're right!

Sign up to save your progress!

Log in with Facebook Log in with Google Log in with email

Join using Facebook Join using Google Join using email

Forgot password? New user? Sign up

Existing user? Log in

by Sakanksha Deo

×

Problem Loading...

Note Loading...

Set Loading...