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See Reese

Algebra Level 2

The $n^{th}$ term of the series $1^2 , ( 1^2 + 2^2 ) , ( 1^2 + 2^2 + 3^2 )$ , $\ldots$ is?

\frac{ n(n + 1)(2n + 1) }{6}

\frac{ n(n + 1) }{2}

\frac{n^2 (n + 1)^2 }{2}

n^2 + (n - 1)^2 + (n - 2)^2

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by Sakanksha Deo

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