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∑n=150n2+3n+1n2+3n+2\sum_{n=1}^{50} \frac{n^2+3n+1}{n^2+3n+2}n=1∑50n2+3n+2n2+3n+1 If the above series can be expressed as AB\frac A BBA, where AAA & BBB both are coprime positive integers, then find A+BA+BA+B.
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