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∑n=148log(nn2+3n+2) \large \sum_{n=1}^{48} \log \left ( \frac {n}{n^2+3n+2} \right )n=1∑48log(n2+3n+2n)
If the summation above equals to SSS, then S+log(49!)=−logP.S+\log(49!)=-\log P.S+log(49!)=−logP. Find the value of PPP.
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