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∑n=148(n3−3n−1)(n+1)! \large \sum_{n=1}^{48} \frac {(n^3-3n-1)}{(n+1)!} n=1∑48(n+1)!(n3−3n−1)
If the summation above equals to SSS, find the value of (49!×S) (49!\times S) (49!×S).
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