# Shifting the numbers, part 4

Logic Level 5

$\frac{\overline{A_1A_2A_3\ldots A_{n-1}A_n}}{\overline{A_3\ldots A_{n-1}A_nA_1A_2}}=\frac{12}{17}$

What is the smallest value of $$n>6$$ such that there exist solutions to the above equation?

Remark: $$\overline{A_1A_2A_3\ldots A_{n-1}A_n}$$ is a $$n$$-digit number. When $$n=6$$, there exist solutions to the above equation. Try it!

This question is part of the set Shifting the numbers.

×