New user? Sign up

Existing user? Log in

\[ \frac{1}{(x-1)(x-2)} + \frac{1}{(x-2)(x-3)} + \frac{1}{(x-3)(x-4)} = \frac{1}{6} \]

What is the sum of all real values of \(x\) that satisfy the above equation?

Problem Loading...

Note Loading...

Set Loading...