Find the slope of the tangent to the curve \[y=\dfrac{1}{2x}+3\] at the point where \(x=-1\). Find the angle which this tangent makes with the curve \[y=2x^2+2, \text{ where } x < 0\]

Submit your answer as the angle in degrees.

You may use the fact that \(\arctan \left( \dfrac{1}{2} \right)\approx 26^\circ\).

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