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If ab+bc+ca=0ab+bc+ca=0ab+bc+ca=0 ,then evaluate 1a2−bc+1b2−ca+1c2−ab\frac {1}{a^2-bc}+\frac {1}{b^2-ca}+\frac {1}{c^2-ab}a2−bc1+b2−ca1+c2−ab1 a,b,ca,b,ca,b,c are positive numbers such that a+b+c≠0a+b+c \ne 0a+b+c=0
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