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Find A+BA+BA+B given that AAA and BBB are constants such that
2x−9x2−x−6=Ax−3+Bx+2.\frac{2x-9}{x^2-x-6}=\frac{A}{x-3}+\frac{B}{x+2}.x2−x−62x−9=x−3A+x+2B.
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