A right angled triangle \(ABC\) (non-isosceles) was cut from a piece of paper as shown in Fig.1.

A point \(E\) was taken at the mid-point of hypotenuse and the figure was folded along \(DE\) such that \(A\) coincides with \(C\). As a result, two separate right triangles \(CBD\) and \(CED\) were formed. (Fig. 2)

Take \(AC = h\), \(AB = p\), \(BC = b\).

Which of these answer choices is equal to the ratio \( \dfrac{ AC}{CD} \)?

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