Simple as ABC!
Geometry
Level
3
A point \(E\) was taken at the mid-point of hypotenuse and the figure was folded along \(DE\) such that \(A\) coincides with \(C\). As a result, two separate right triangles \(CBD\) and \(CED\) were formed. (Fig. 2)
Take \(AC = h\), \(AB = p\), \(BC = b\).
Which of these answer choices is equal to the ratio \( \dfrac{ AC}{CD} \)?
by
Tapas Mazumdar