# Simple isn't enough

Calculus Level 4

$\int_{0}^{16} { \arctan{(\sqrt{\sqrt{z} -1})} \ dz}$

If the complex integral above can be expressed as $$a + ib$$. Find the value of $$\left \lfloor{a + 10b}\right \rfloor$$.

Clarification: $$i = \sqrt{-1}$$.

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