\[\int_{0}^{16} { \arctan{(\sqrt{\sqrt{z} -1})} \ dz}\]

If the complex integral above can be expressed as \(a + ib\). Find the value of \(\left \lfloor{a + 10b}\right \rfloor \).

**Clarification**: \(i = \sqrt{-1}\).

×

Problem Loading...

Note Loading...

Set Loading...