\[\large{L=\lim_{n \to \infty} \left( \dfrac1{3^5} + \dfrac2{4^5} + \dfrac3{5^5} + \ldots + \dfrac{n}{(n+2)^5} \right)}\]

Choose the correct option.

You are given that \(\zeta(5) \approx 1.03692\).

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