Triple Double Set

There are triplets of positive integers satisfying 2x+2y+2z=23362^{x} + 2^{y} + 2^{z} = 2336

Evaluate i=1n(xi+yi+zi) \displaystyle \sum_{i = 1}^{n} (x_{i} + y_{i} + z_{i} )

  • Dedicated to Brian Charlesworth

  • Brian Charlesworth's challenge - generalize the problem( for odds , evens and primes) , you will be appriciated

×

Problem Loading...

Note Loading...

Set Loading...