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There are triplets of positive integers satisfying 2x+2y+2z=23362^{x} + 2^{y} + 2^{z} = 23362x+2y+2z=2336
Evaluate ∑i=1n(xi+yi+zi) \displaystyle \sum_{i = 1}^{n} (x_{i} + y_{i} + z_{i} )i=1∑n(xi+yi+zi)
Dedicated to Brian Charlesworth
Brian Charlesworth's challenge - generalize the problem( for odds , evens and primes) , you will be appriciated
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