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1+x+x2+x3+⋯1+2x+3x2+4x3+⋯ \dfrac{1+x+x^2+x^3+\cdots}{1+2x+3x^2+4x^3+\cdots } 1+2x+3x2+4x3+⋯1+x+x2+x3+⋯
For ∣x∣<1|x| < 1∣x∣<1, find the closed form of the expression above.
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