Could I use telescoping sum?

Calculus Level 4

$\large \lim_{x \to 0} \left (1^{\frac 1 {\sin^2 x}} + 2^{\frac 1 {\sin^2 x}} + 3^{\frac 1 {\sin^2 x}} + \ldots + n^{\frac 1 {\sin^2 x}} \right )^{\sin^2 x } = \ ?$

\infty

n

1

None of these choices

\frac{n+2}{2}

0