Skydiver

Calculus Level 1

Two forces act on a parachutist. One is $mg,$ the attraction by the earth, where $m$ is the mass of the person plus equipment and $g=9.8 \text{ m/sec}^2$ is the acceleration of gravity. The other force is the air resistance ("drag"), which is assumed to be proportional to the square of the velocity $v(t)$ .

Using Newton's second law of motion (mass $\times$ acceleration = net force applied), set up an ordinary differential equation for $v(t).$

Let $k$ denote the drag coefficient.

mg-k{v}^{2}=m\frac { dv }{ dt }

mg=m\frac { dv }{ dt }

mg-k{v}^{2}=m\frac { d{v}^{2} }{ d{t}^{2} }

mg-{k}^{2}{v}^{2}=m\frac { dv }{ dt }

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