A truck of width \(l\) is moving with a uniform speed \({v}_{0}\) along a straight horizontal road. A pedestrian starts to cross the road with a uniform speed \(u\) when the truck is \(d\) away from him. The minimum value of \(u\) so that he can cross the road safely is of the form \(\frac{m}{\sqrt{n}}\) where \(m\) and \(n\) are coprime and \(n\) is square free. Find \(m-n\).

\(l=2m\\{v}_{0}=8m{s}^{-1}\\d=4m\)

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